semoga bermanfaaat...........
NOMOR 11. (B)
[tex] { ({64}^{ \frac{3}{2} }) }^{ \frac{1}{3} } = ( {64}^{ \frac{3}{2} \times \frac{1}{3} } ) = ( {64}^{ \frac{1}{2} } ) = \sqrt{64} = 8[/tex]
NOMOR 12. (B)
[tex]( { {16}^{ \frac{1}{4} }) }^{ - 3} = ( {16}^{ \frac{ - 3}{4} } ) = \frac{1}{( {16}^{ \frac{3}{4} }) } = \frac{1}{( { ({2}^{4} )}^{\frac{3}{4} } )} = \frac{1}{ {2}^{3} } = \frac{1}{8} [/tex]
NOMOR 13. (D)
[tex]( { {27}^{ \frac{1}{2} }) }^{ \frac{ - 4}{3} } = ({27})^{ \frac{ - 2}{3} } = \frac{1}{({27})^{ \frac{2}{3} } } = \frac{1}{( { {3}^{3} )}^{ \frac{2}{3} } } = \frac{1}{ {3}^{2} } = \frac{1}{9} [/tex]
NOMOR 14. (A)
[tex] \frac{ {3}^{2} + {3}^{2} + {3}^{2} }{ {2}^{3} + {2}^{3} + {2}^{3} } = \frac{3 \times {3}^{2} }{3 \times {2}^{3} } = \frac{ {3}^{3} }{3 \times 8} = \frac{ {3}^{3 - 1} }{8} = \frac{ {3}^{2} }{8} = \frac{9}{8} [/tex]
NOMOR 15. (B)
[tex] {(3 {a}^{4} {b}^{ - 3} ) }^{2} = {3}^{2} {a}^{4 \times 2} {b}^{ - 3 \times 2} = 9 {a}^{8} {b}^{ - 6} = \frac{9 {a}^{8} }{ {b}^{6} } [/tex]
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